Total no. of possible outcomes = 20 {5 red, 8 white & 7 black}

**(i) E ⟶ event of drawing red or white ball**

No. of favourable outcomes = 13 {5 red, 8 white}

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)

P(E) = 13/20

**(ii) Let E ⟶ be event of getting black ball**

No. of favourable outcomes = 13 {5 red, 8 white}

P(E) = 7/20

(Bar E)⟶ event of not getting black ball

P(Bar E) = 1 – P(E)

=1−7/20 = 13/20

**(iii) Let E ⟶ be event of getting neither white nor black ball**

No. of favourable outcomes = 20 – 8 – 7 = 5 {total balls – no. of white balls – no. of black balls}

P(E) = 5/20 = 1/4